SOLUTION: susan built a flowerbed. the perimeter of the flower bed is 42 feet, and its length is 9 feet less than twice its width. find the lenth and width of the flower bed.

Question 881148: susan built a flowerbed. the perimeter of the flower bed is 42 feet, and its length is 9 feet less than twice its width. find the lenth and width of the flower bed.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

     .

L + w = 21

(2w-9) + w = 21

    3w = 30

     w = 10ft and L is 11ft 

RELATED QUESTIONS

Please help me solve this word problem:

The length of a rectangular flower bed is 3... (answered by 067isa,checkley71,TakeATuition.com)
 The length of arectangular flower bed is 3 feet less than twice its width. the area of... (answered by edjones)
The length of a rectangular flower bed is 11 feet less than 3 times its width. The area... (answered by graphmatics)
A rectangle's length is 3 feet less than twice its width. The perimeter is 42 feet. What... (answered by checkley77)
The length of a rectangle flower bed is 7 feet less than 3 times its width.  The area of... (answered by solver91311)
The length of a rectangle is 9 feet less than twice its width. The perimeter is 54 feet.... (answered by stanbon)


The width of a rectangular flower bed is 3 meters less than its length. The area of... (answered by checkley79)
A rectangular flower bed is eight feet longer than it is wide. If the area of the flower... (answered by checkley77)