SOLUTION: The area of a rectangle is 33m^2, and the length of the rectangle is 5 m less than double the width. Find the dimensions of the rectangle

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Question 874852: The area of a rectangle is 33m^2, and the length of the rectangle is 5 m less than double the width. Find the dimensions of the rectangle
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
A = Lw = 33m^2
(2w-5)w = 33
2w^2 - 5w - 33 = 0, w = 5.5m and L = 6m
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=289 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 5.5, -3. Here's your graph:
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