SOLUTION: The length of a rectangle is 5 cm longer than the width. The perimeter of the rectangle is 50 cm. Find the length and width of the rectangle.

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Question 866589: The length of a rectangle is 5 cm longer than the width. The perimeter of the rectangle is 50 cm. Find the length and width of the rectangle.
Found 2 solutions by JulietG, josgarithmetic:
Answer by JulietG(1812)   (Show Source): You can put this solution on YOUR website!
2L + 2W = 50
L = W+5
Substitute the value of L from the second equation into the first.
2(W+5) + 2W = 50
2W+10 + 2W = 50
4W + 10 = 50
Subtract 10 from each side.
4W = 40
Divide each side by 4
W = 10
.
If the width is 10, then the length is 10+5, or 15.

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
w=width
L=length
Formula for perimeter, p=2(w+L)
Given:
p=50




Substitute,





Actual correct steps can vary some, but w, if in symbolic form must be equivalent to the green-outlined formula shown. Just substitute for the given p value of 50, and compute w.
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You could do all this without being in pure symbolic form - it's up to you; but it depends on how many of this general type of rectangle exercise you have. This is a very frequent type of exercise problem and generalizing its solution can be more efficient if you have many of these.

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