SOLUTION: The area of a rectangle is 55 yd^2 , and the length of the rectangle is 4yd less than three times the width, what is the length & width
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Question 862818: The area of a rectangle is 55 yd^2 , and the length of the rectangle is 4yd less than three times the width, what is the length & width
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Simple algebra applied to rectangle.
A = 55 yd^2
L = length
w = width
k = 4 yd
m = the factor, 3
-
.
.
Substitute for L in the A equation.
WHAT NEXT?
Use the general solution of a quadratic equation to solve for w. Substitute the given values for k, A, and m and compute w. Use the now found value of w to compute L.
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