SOLUTION: the length of a rectangle is 2in longer than its width. if the perimeter is 36in, what is the area?

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Question 862466: the length of a rectangle is 2in longer than its width. if the perimeter is 36in, what is the area?
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The length of a rectangle is k inches more than its width. If perimeter p is known, what is area A?

Let L = length
Let w = width
k is a described constant, as is p.
A is a variable, unknown, but calculable, for the area.
-
.






Use w to find L.

------this form may be good enough...


-------this form seems better.

Now, you want Area A, and you begin forming .



The solution is generalized. You should now appreciate the use of purely solving all in symbols. You have a formula for the area which was asked. What would be important is that the values for p and k make sense in the described situation. Their actual values are not too important; only that they make sense in the situation is important. In your example, p=36 and k=2. Use them and compute A.
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