SOLUTION: the width of a rectangle is 5cm greater than its length. if the area of the reactangle is 124cm^2, what are the approximate dimensions of the rectangle?

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Question 860161: the width of a rectangle is 5cm greater than its length. if the area of the reactangle is 124cm^2, what are the approximate dimensions of the rectangle?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Let x represent the length. The width is (x+5)
x(x+5) = 124cm^2
x^2 + 5x = 124
x^2 + 5x - 124 = 0
x = `8.9, the length. The width ` 13.9
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=521 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 8.91271221051333, -13.9127122105133. Here's your graph:

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