SOLUTION: A rectangle has a length of x. It's width is 3 feet longer than twice the length. Find the dimensions if its area is 80 feet squared.

Algebra.Com
Question 848331: A rectangle has a length of x. It's width is 3 feet longer than twice the length. Find the dimensions if its area is 80 feet squared.
Answer by swincher4391(1107)   (Show Source): You can put this solution on YOUR website!
x(2x+3) = 80
2x^2 + 3x - 80 = 0
using the quadratic formula we get
= 5.62ft
2(5.62)+ 3 = 14.24
5.62 x 14.24



RELATED QUESTIONS

The length of a rectangle is 4 feet longer than twice its width. If its area is 336 sq... (answered by rapture)
The length of a rectangle is 3 feet longer than twice the width. If the area is 54 square (answered by TimothyLamb)
a rectangle has a length that is 3 meters longer than twice the width what are the... (answered by Fombitz)
If the length of a rectangle is 3 feet longer than its width and the diagonal is (answered by solver91311)
The length of a rectangle storage room is 4 feet longer than its width. If the area of... (answered by SHUgrad05)
the width of a rectangle is 6 feet less than twice its length. If its area is 108 square... (answered by TimothyLamb,srinivas.g)
The length of a rectangular banner is 2 feet longer than its width. If the area is 80 (answered by checkley79)
the length of a rectangle is 2 inches greater than twice the width and it has an area of... (answered by stanbon)
if the length of a rectangle is 3 feet greater than the width and it has an area of 28... (answered by JBarnum)