SOLUTION: Andrew wants to divide his rectangular garden into two parts diagonally. The garden has a length of 40 feet and width 30 feet. What will be the area of each section of the garde

Question 846747: Andrew wants to divide his rectangular garden into two parts diagonally. The garden has a length of 40 feet and width 30 feet.
What will be the area of each section of the garden after the division?
Answer by pmesler(52) (Show Source): You can put this solution on YOUR website!
First, draw a rectangle. Label the width 30 and the length 40. Then draw a diagonal across the entire rectangle. This forms two right triangles. This diagonal is the hypotenuse that both right triangles share, one for each side. To find the area of a triangle use the formula
A = b * h/2. Here the base, b is the length, and the width w, is the height h.
Therefore the area is
A = 30 * 40 / 2 = 120/2 = 60
Therefore the area for each section of the garden will be 60 square feet.
RELATED QUESTIONS
Alex\ is\ building\ a\ rectangular\ garden\ that\ has\ an\ area\ of\ 912\ square\ feet.\... (answered by josgarithmetic,Alan3354)

A gardener has 270 feet of fencing and wants to fence in a rectangular garden and then... (answered by josgarithmetic)

a rectangular garden has width w and length 1.5w. the area of the garden is 216 square... (answered by TimothyLamb)

david currently has a square garden. He wants to redesign his garden and make it into a... (answered by Theo)

David currently has a square garden He wants to redesign his garden and make into a... (answered by josgarithmetic,MathTherapy)

Frank buys fencing for a rectangular garden he has in his backyard. The length of the... (answered by Boreal)

Maureen Woolhouse has a rectangular garden whose width is two-thirds its length. If its... (answered by CubeyThePenguin)

Wilma is fencing in her rectangular garden. She wants the length to be 30 feet greater... (answered by jorel1380)

You have 480 feet of fencing to enclose a rectangular garden. You want the length of the... (answered by ankor@dixie-net.com)