SOLUTION: The length of a rectangle is 6in longer than its width.
If the perimeter of the rectangle is 44in , find its area.
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Question 841669: The length of a rectangle is 6in longer than its width.
If the perimeter of the rectangle is 44in , find its area.
Answer by Narsinghchauhan8960103366(17) (Show Source): You can put this solution on YOUR website!
Let the width of rectangle is x in
So the length is (x+6) in
According to question
Perimeter of Rectangle =2(length+width)
44=2[(x+6)+x]
44=2(2x+6)
44=4x+12
4x=44-12=32
x=32/4=8 in
width =8 in
length =8+6=14
Perimeter of Rectangle = length*width
=14*8=112 square in
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