SOLUTION: The area of a rectangle of length x is given by 3x^2+5x. Find the width of the rectangle. How do I do this?

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Question 84091: The area of a rectangle of length x is given by 3x^2+5x. Find the width of the rectangle. How do I do this?
Found 2 solutions by checkley75, ankor@dixie-net.com:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
AREA OF A RECTANGLE=SIDE1*SIDE2. SO WE NEED TO FACTOR THIS ANSWER INTO 2 PARTS SIDE1 & SIDE2 THUS:
3X^2+5X
X(3X+5) X BEING SIDE 1 THEN (3X+5) IS SIDE2.

Answer by ankor@dixie-net.com(12692) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle of length x is given by 3x^2+5x. Find the width of the rectangle. How do I do this?
:
You know that:
L * W = A
:
In this problem; L is given as x and A is give (3x^2 + 5x); so we have:
x * W = 3x^2 + 5x
:
Divide both sides by x:
W = %28%283x%5E2+%2B+5x%29%29%2Fx
:
Divide both terms by x and you have:
W = 3x + 5; is the width
:
:
Check: L * W would be x*(3x+5) = 3x^2 + 5x which is given as the area
:
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