SOLUTION: On this particular problem you are to refer to the rectangle, but I don't know how to add the rectangle into this page for a visual effect, but this is the directions and the measu

Algebra ->  Algebra  -> Rectangles -> SOLUTION: On this particular problem you are to refer to the rectangle, but I don't know how to add the rectangle into this page for a visual effect, but this is the directions and the measu      Log On

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Question 83593: On this particular problem you are to refer to the rectangle, but I don't know how to add the rectangle into this page for a visual effect, but this is the directions and the measurements that I have.
Find the perimeter of the given rectangle: The measurements that I have are: Top part of rectangle (length) is x/2x-5 and the width line on the right is 8/2x-5.
I hope that this is enough to understand what is needed and please explain step by step for me. Thank You.
Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
Since the perimeter is
P=2L%2B2w

we can factor out a 2 to make the equation

P=2%28L%2Bw%29

Now plug in L=x%2F%282x-5%29 and w=8%2F%282x-5%29

P=2%28x%2F%282x-5%29%2B8%2F%282x-5%29%29

Since we have a common denominator, we can add the fractions


P=2%28%28x%2B8%29%2F%282x-5%29%29 Combine the fractions


P=%282x%2B16%29%2F%282x-5%29 Multiply

So the perimeter of a rectangle with a length of x%2F%282x-5%29 and a width of8%2F%282x-5%29 is %282x%2B16%29%2F%282x-5%29