SOLUTION: The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is 58 feet. Find the width of the rectangle.
I don't quite get these so far I got 2w + 2
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Question 835357: The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is 58 feet. Find the width of the rectangle.
I don't quite get these so far I got 2w + 2l = 58.
Help?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
w for width
L for Length
; and .
NOW can you see how to continue? The first sentence gave you the equation for L equals something.
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