SOLUTION: The perimeter of a rectangle is 46 feet. The width is 3ft. less than twice the length. Find the length and the width of the rectangle. P=2L+2W 46=2L+2(2L-3) 46=2L+4L-6 52=6

Question 833950: The perimeter of a rectangle is 46 feet. The width is 3ft. less than twice the length. Find the length and the width of the rectangle.
P=2L+2W
46=2L+2(2L-3)
46=2L+4L-6
52=6L
L=8.66
46=2(8.66)+2(2(8.66)-3)
46=17.32+2(17.32-3)
46=17.32+2(14.32)
46=17.32+28.64
46=45.96 ft.
L=8.66 ft. W=14.32 ft.
I'm not sure if this is correct since I kept getting decimals.
Thanks!!!

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
8.6667 is correct or you can leave it as a mixed number 8 2/3
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