SOLUTION: The length of a rectangle is 5 in longer than its width.
If the perimeter of the rectangle is 42 in, find its area.
Algebra.Com
Question 830442: The length of a rectangle is 5 in longer than its width.
If the perimeter of the rectangle is 42 in, find its area.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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x = y + 5
2x + 2y = 42
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put the system of linear equations into standard form:
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x - y = 5
2x + 2y = 42
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 13 in
y = 8 in
area = 8*13 = 104 sq.in
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Solve systems of linear equations up to 6-equations 6-variables:
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