SOLUTION: a rectangle with perimeter of 52 inches has a length to width ratio of 8 to 5. find the length and width of the rectangle
Algebra.Com
Question 829254: a rectangle with perimeter of 52 inches has a length to width ratio of 8 to 5. find the length and width of the rectangle
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
---
2x + 2y = 52
x/y = 8/5
---
put the system of linear equations into standard form:
---
2x + 2y = 52
5x = 8y
---
2x + 2y = 52
5x - 8y = 0
---
copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = length = 16 in
y = width = 10 in
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
RELATED QUESTIONS
The length of a rectangle is 8 inches and its width is 5 inches. Find the ratio of length (answered by jim_thompson5910,55305)
The ratio of the width to the length of a rectangle is 5:6. The perimeter of the... (answered by stanbon)
The perimeter of a rectangle is 144 ft. The ratio of the width to the length is 3:5. Find (answered by jim_thompson5910)
Find the dimensions of a rectangle with a perimeter of 126 feet and length and width... (answered by edjones)
The Perimeter of a rectangle is 27 inches. The ratio of the length to the width is 2:1.... (answered by solver91311)
The perimeter of a rectangle is 65 inches. The ratio of the length to the width is 4:1.... (answered by rfer)
The perimeter of a rectangle is 24 inches. The ratio of the length to the width is 2:1.... (answered by mananth)
the perimeter of a rectangle is 56 inches. the ratio of the length to the width is 6:1.... (answered by stanbon)
A rectangle has a perimeter of 70. What is the 4 to 5 (length to width) ratio of this... (answered by cleomenius)