SOLUTION: [ If a rectangle has a perimeter of 3600 meters, what is the width if the length is 5 times the width ]

Question 825409: [ If a rectangle has a perimeter of 3600 meters, what is the width if the length is 5 times the width ]
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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x = width
y = length
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3600 = 2x + 2y
y = 5x
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put the system of linear equations into standard form
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2x + 2y = 3600
5x - y = 0
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution by matrix method:
x = width = 300 m
y = length = 1500 m
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system matrix
2 2
5 -1
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inverse of system matrix
0.083333333 0.16666667
0.41666667 -0.16666667
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determinant of system matrix = -12
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now solve by substitution method:
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3600 = 2x + 2y
y = 5x
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3600 = 2x + 2(5x)
3600 = 2x + 10x
12x = 3600
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solution by substitution method:
x = width = 300 m
y = length = 1500 m
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NOTE:
solution by matrix method agrees with solution by substitution method.
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---
Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 4-equations 4-variables:
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