SOLUTION: the area of the rectangle is x^3 -2x^2 -5x+6 square feet. If its length is x-3 feet, what is its width?
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Question 823405: the area of the rectangle is x^3 -2x^2 -5x+6 square feet. If its length is x-3 feet, what is its width?
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
Since area = L * W
x^3 -2x^2 -5x+6 = ( x-3 )( W )
and
W =
Here is the long division.
_________
(x-3)|
_____
________
________
___________
___________
________________0
So the width is .
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