SOLUTION: The length of a rectangle is twice its width.
If the area of the rectangle is 200cm ^2 , find its perimeter.
Algebra.Com
Question 822519: The length of a rectangle is twice its width.
If the area of the rectangle is 200cm ^2 , find its perimeter.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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L = 2w
Lw = 200
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Lw = 200
2ww = 200
2ww - 200 = 0
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the above quadratic equation is in standard form, with a=2, b=0, and c=-200
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
2 0 -200
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has two real roots (the x-intercepts), which are:
w = 10
w = -10
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negative width doesn't make sense for this problem, so use the positive root
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w = 10 cm
L = 20 cm
perimeter = 60 cm
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Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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