SOLUTION: The width of a rectangle is 2 yards shorter than its length. the area of the rectangle is 48 square yards. find the length and width of the rectangle.

Question 818156: The width of a rectangle is 2 yards shorter than its length. the area of the rectangle is 48 square yards. find the length and width of the rectangle.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
w = L - 2
Lw = 48
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Lw = 48
L(L - 2) = 48
LL - 2L = 48
L^2 - 2L - 48 = 0
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the above quadratic equation is in standard form, with a=1, b=-2, and c=-48
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to solve the quadratic equation, plug this:
1 -2 -48
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the roots of the quadratic are:
h = 8
h = -6
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the negative root doesn't make sense for a length, so use the positive root:
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Answer:
L = 8 yards
w = 6 yards
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