SOLUTION: the area of a rectangle is 99 yd^2, and the length of the rectangle is 7 yd more than twice the width. what are the dimensions of the rectangle?

Question 814513: the area of a rectangle is 99 yd^2, and the length of the rectangle is 7 yd more than twice the width. what are the dimensions of the rectangle?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
Lw = 99 sq.yd
L = 2w + 7
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Lw = 99
(2w + 7)w = 99
2ww + 7w = 99
2ww + 7w - 99 = 0
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the above quadratic equation is in standard form, with a=2, b=7, and c=-99
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to solve the quadratic equation, plug this:
2 7 -99
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the roots of the quadratic are:
-9
5.5
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the negative root doesn't make sense as a length, so use the positive root:
---
w = 5.5
L = 18
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