SOLUTION: The length of a rectangle is 5 YARDS more than double the width, and the area of the rectangle is 63 YARDS . Find the dimensions of the rectangle.

Question 809801: The length of a rectangle is 5 YARDS more than double the width, and the area of the rectangle is 63 YARDS . Find the dimensions of the rectangle.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
L = 2W + 5
A = LW = 63
L = 63/W
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L = 2W + 5
63/W = 2W + 5
63 = 2WW + 5W
2WW + 5W - 63 = 0
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2WW + 5W - 63 = 0
is already in quadratic equation form: ax^2 + bx + c = 0
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use the quadratic formula to solve for two solutions:
x = ( -b +- sqrt( bb - 4ac ) ) / 2a
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the two solutions are:
x = 9/2
x = -7
the negative solution doesn't make sense for length, so use the positive solution.
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W = 9/2
L = 14
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