SOLUTION: If a classroom has a length that is 5 feet less than two times its width and its perimeter is 80 feet,find width and length of the classroom?
Algebra.Com
Question 809014: If a classroom has a length that is 5 feet less than two times its width and its perimeter is 80 feet,find width and length of the classroom?
Answer by vheroli(126) (Show Source): You can put this solution on YOUR website!
Formulas:
P= 2L + 2W
L= 2x - 5
W= x
Solution:
80 = [ 2(2x-5) ] + 2(x) :Simplify
80 = (4x-10) + 2x : Simplify
80 = 6x - 10 : Simplify
80 + 10 = 6x
90 = 6x : Solve for x
90/6 = x
15 = x
Answers:
L= 2x - 5
L= 2 (15) - 5
L= 30-5
L= 25 ft
W= x
W= 15 ft
RELATED QUESTIONS
The perimeter of a rectangle is 80 feet, and it's length is 5 feet less than twice its... (answered by algebrahouse.com)
The area of a rectangular wall in a classroom is 264 square feet. Its length is 9 feet... (answered by jorel1380)
The area of a rectangular wall in a classroom is 171 square feet. Its length is 8 feet... (answered by josgarithmetic,greenestamps)
The area of a rectangular wall in the classroom is 216 square feet. Its length is 3 feet (answered by FrankM)
A rectangle has a perimeter of 14 feet. If the twice its length is equal to one less... (answered by drj)
A rectangle has a perimeter of 14 feet, and twice its length l is equal to two more than... (answered by oberobic)
The length of a rectangle is 2 feet less than twice its width. If the perimeter is 26... (answered by Cromlix)
It has to be 2 feet high, and the width is to be 3 feet less than its length. If it needs (answered by mananth)
The length of a rectangle is 4 feet more three times its width. Find the largest possible (answered by checkley77)