SOLUTION: the length of a rectangle is 8 feet more than twice its width. if the perimeter of the rectngle is 52 feet what is the length and width?

Question 808332: the length of a rectangle is 8 feet more than twice its width. if the perimeter of the rectngle is 52 feet what is the length and width?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
L = 2W + 8
P = 2L + 2W = 52
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2L + (L - 8) = 52
3L - 8 = 52
3L = 60
L = 20
W = (L - 8)/2 = (20 - 8)/2
W = (12)/2 = 6
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Answer:
L = 20
W = 6
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