SOLUTION: The length of a rectangle is 5 cm more than its width. Find the length and width if the area is 104 cm^2.
Is this correct?
(x)(x+5x)=104cm^2
x^2+5x=104cm^2
(x^2+5x-104cm^2)=
Algebra.Com
Question 807932: The length of a rectangle is 5 cm more than its width. Find the length and width if the area is 104 cm^2.
Is this correct?
(x)(x+5x)=104cm^2
x^2+5x=104cm^2
(x^2+5x-104cm^2)= (x^2+5x-104cm)
(x+13)=0(x-5)=0
x=-13 x=5
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 5 cm more than its width. Find the length and width if the area is 104 cm^2.
Is this correct?
(x)(x+5x)=104cm^2
x^2+5x=104cm^2
(x^2+5x-104cm^2)= (x^2+5x-104cm)
(x+13)=0(x-5)=0
x=-13 x=5
--------------------
13 by 5 --> 65 sq cm, not 104
============================
Is this correct?
(x)(x+5x)=104cm^2 ************* It's x*(x+5) = 104
-------------
Factor 104:
1*104
2*52
4*26
8*13 works.
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