SOLUTION: The perimeter of a rectangle is 46 meters. Twice the length is 4 more than five times the width. Find the demensions of the rectangle

Question 799397: The perimeter of a rectangle is 46 meters. Twice the length is 4 more than five times the width. Find the demensions of the rectangle
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Let w = the width of the rectangle
Let l = the length of the rectangle
The formula for the perimeter is
(1) p = 2l + 2w
We are given;
(2) p = 46 and
(3) 2l = 5w + 4
The perimeter is given by
(4) 2l + 2w = 46
Now put 2l given by (3) into (4) to get
(5) 5w + 4 + 2w = 46 or
(6) 7w = 46 - 4 or
(7) 7w = 42 or
(8) w = 6
Now use (3) to find l
(9) 2l = 5*6 + 4 or
(10) 2l = 34 or
(11) l = 17
Always check your answer. We can do this with (1).
Is (2*17 + 2*6 = 46)?
Is (34 + 12 = 46)?
Is (46 = 46)? Yes
Answer: The dimensions of the rectangle are 17m and 6m.

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