SOLUTION: Let the width of a rectangle be w. The length of the rectangle is six less than double the width.
A.) Write an equation to represent the area.
B.) Write an expression to repres
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Question 789724: Let the width of a rectangle be w. The length of the rectangle is six less than double the width.
A.) Write an equation to represent the area.
B.) Write an expression to represent the perimeter.
C.) Solve the equation if the perimeter is 30 inches.
D.) Tell the dimensions of the rectangle.
Answer by waynest(281) (Show Source): You can put this solution on YOUR website!
l = 2w - 6
A.) A = lw
A = w(2w - 6)
A = 2w^2 - 6w
B.) P = 2L + 2w
P = 2(2w - 6) + 2w
P = (4w - 12) + 2w
P = 6w -12
C.) 30 = 6w - 12
30 + 12 = 6w - 12 + 12
42 = 6w
42/6 = 6w /6
7 = w
D.) width = 7 inches
length = 2(7) - 6 = 8 inches
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