SOLUTION: a rectangle has a perimeter of 68 feet. its length is 5 less than twice its width. find the area of the rectangle?
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Question 787072: a rectangle has a perimeter of 68 feet. its length is 5 less than twice its width. find the area of the rectangle?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Width = x
Length = 2x - 5
Perimeter = 2*width + 2*length
68 = 2(x) + 2(2x - 5)
68 = 2x + 4x - 10
68 + 10 = 6x
78 = 6x
x = 13 feet
Width = 13 feet
Length = 21 feet
Area = Width * Length
Width = 13 * 21
Width = 273 feet^2
Hope this helps.
:-)
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