SOLUTION: The length of a rectangle is 1 feet less than twice the width. The perimeter is 73. Find the width.

Algebra.Com
Question 776020: The length of a rectangle is 1 feet less than twice the width. The perimeter is 73. Find the width.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 1 feet less than twice the width. The perimeter is 73. Find the width.
--------------------
L = 2W - 1
2L + 2W = 73
-----------
Sub for L in eqn 2
2(2W - 1) + 2W = 73
Can you finish it?

RELATED QUESTIONS

the length of a rectangle is 1 foot less than twice the width. perimeter is 40 feet. find (answered by waynest)
The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet.... (answered by ewatrrr)
The length of a rectangle is 3 feet less than twice its width and the perimeter is 72... (answered by stanbon)
Suppose the perimeter of a rectangle is 200 feet and the length of the rectangle is 5... (answered by mananth)
the lenght of a rectangle is 4 feet less than twice the width. the perimeter is 28 feet.... (answered by vleith)
The perimeter of a rectangle is 46 feet. The width is 3ft less than twice the length.... (answered by oscargut)
The length of a rectangle is 6 feet less than twice the width. The perimeter is 66 feet.... (answered by checkley77)
the length of a rectangle is 3 feet less than twice the width. The perimeter is 54 feet.... (answered by solver91311)
The length of a rectangle is 6 feet less than twice the width. The perimeter is 48 feet.... (answered by JBarnum)