SOLUTION: Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice the shorter side. Find its length and width.

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Question 769007: Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice the shorter side. Find its length and width.
Answer by ramkikk66(644)   (Show Source): You can put this solution on YOUR website!

Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice the shorter side. Find its length and width.
Ans:
If 2 rectangles are similar, it means that their sides are proportional to each
other. I.e. if the first rectangle has length and width of L1 and W1, and the
second one has L2 and W2, L1/W1 = L2/W2.
Here, L1 = 5, W1 = 12
In the second rectangle, let the shorter side (width) be x. Then the longer
side (length) is given to be 2*x + 8
Since the sides are proportional, we get the equation
Cross multiplying
Simplifying


Shorter side of second rectangle (width) = 20 cm
Longer side = length = 2*20 + 8 = 48 cm
:)
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