SOLUTION: The length of a rectangle is 1yd more than twice its width, and the area of the rectangle is 45yd^2 . Find the dimensions of the rectangle.
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Question 762706: The length of a rectangle is 1yd more than twice its width, and the area of the rectangle is 45yd^2 . Find the dimensions of the rectangle.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Area is 
. But 
, so \ =\ 2w^2\ +\ w)
. If 
then:
Put the quadratic into standard form and solve for 
. Discard the absurd negative root. Then calculate 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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