SOLUTION: If the width of a rectangle is three fourths of the length. the perimeter of the rectangle becomes 50cm when the length and the width are each increased by 2cm. what is the length

Question 761808: If the width of a rectangle is three fourths of the length. the perimeter of the rectangle becomes 50cm when the length and the width are each increased by 2cm. what is the length and the width of the rectangle?
Answer by danishsiddiqui1000(2) (Show Source): You can put this solution on YOUR website!

Let x = length of rectangle
Let 3x/4 = width of rectangle
Perimeter of rectangle P = 2 + 2*
[3x/4]
Perimeter of rectangle = 50 = 2 +
2
That is 50 = 2x + 4 + 2
50 = 2x + 4 + (3x + 8)/2
50 = (4x + 8 + 3x + 8)/2
100 = 4x + 8 + 3x + 8
100 = 7x + 16
84 = 7x
x = 12
Length of rectangle = 12 cm
Width of rectangle = 9 cm = 12*3/4
Check 12+2 = 14 ; 9+2 = 11 ; P = 2*14 +
2*11 = 28 + 22 = 50 cm
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