SOLUTION: The perimeter of a rectangle is 76 ft , and the area of the rectangle is 72 ft^2 . Find the dimensions of the rectangle.

Question 752841: The perimeter of a rectangle is 76 ft , and the area of the rectangle is 72 ft^2 . Find the dimensions of the rectangle.
Answer by Okeke_Christian(26) (Show Source): You can put this solution on YOUR website!
Perimeter of Rectangle = 2l + 2b
Area of Rectangle = l * b
Perimeter of Rectangle
= ------------- eqn 1

Area of Rectangle
=
We can remove units and solve.
--------------- eqn. 1
----------------- eqn. 2
From eqn. 2,

Substitute 72/b for l in eqn. 1

Either

Either
=>
OR

When you substitute
into eqn. 2, you get that
AND
When you substitute
into eqn. 2, you get that
Therefore, dimensions of the rectangle are
l=2 and b=36 OR
l=36 and b=2
Hope I helped!
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