SOLUTION: a rectangle has whole number sides.The length of the rectangle is tripled and the width is doubled.the new area is 204 cm squared.the new perimeter is 110 cm.what was the old peri

Question 724205: a rectangle has whole number sides.The length of the rectangle is tripled and the width is doubled.the new area is 204 cm squared.the new perimeter is 110 cm.what was the old perimeter?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
= the length of one of the sides of the new, enlarged rectangle
= the length of the other side of the new, enlarged rectangle
The new area is .
The new perimeter is -->
I could set up to solve , end up with a quadratic equation, and solve it by factoring. The hint that the length of the sides were whole numbers tells me that the factoring approach would work.
Finding two numbers that add up to 55 and multiply to yield 204 is a shorter way to do that.
Since and the new rectangle sides measure and
Since and , it is obvious that the original length and width were and .
(The original length and width could not have been and respectively, because that would gives us a length shorter than the width and no whole number side lengths).
With a length of and a width of , the perimeter of the original rectangle is

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