SOLUTION:
The floor of a room is a rectangle.
It has a perimeter of 22 meters and an area of 24 square meters.
What are the length and width of the room?
Algebra.Com
Question 723279:
The floor of a room is a rectangle.
It has a perimeter of 22 meters and an area of 24 square meters.
What are the length and width of the room?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
P=2L+2W
A=LW
24=LW
L=24/W
22=2(24/W)+2W
22=48/W+2W
22=(48+2W*W)/W
22=(48+2W^2)/W CROSS MULTIPLY.
48+2W^2=22W
2W^2-22W+48=0
2(W^2-11W+24)=0
2(W-3)(W-8)=0
W-3=0
W=3 ANS.
W-8=0
W=8 ANS.
L=24/3=8 ANS.
L=24/8=3 ANS.
PROOF:
22=(48/8)+2*8
22=6+16
22=22
22=(48/3+2*3
22=16+6
22=22
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