SOLUTION: Find the dimentions of a rectangle whose lenth is one foot longer than twice its width and whose perameter is 20 feet.

Question 705761: Find the dimentions of a rectangle whose lenth is one foot longer than twice its width and whose perameter is 20 feet.
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
Set-Up:
Equation 1:
Equation 2: (The perimeter of a rectangle
P = 20
-----------------------------
Since equation 1 is already solved for L, plug (2W + 1) into equation 2 for L
Equation 2:

Multiply the 2 through

Combine like terms

Subtract 2 from both sides

Divide both sides by 6

Now plug 3 into equation 1 for W
Equation 1:

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