SOLUTION: The length of a rectangle is 8in more than twice its wodth. If the perimeter of the rectangle is 64in, find the width of the rectangle.
Multiple choice:
a) 10in
b) 7in
c) 8in
Algebra.Com
Question 70426: The length of a rectangle is 8in more than twice its wodth. If the perimeter of the rectangle is 64in, find the width of the rectangle.
Multiple choice:
a) 10in
b) 7in
c) 8in
d) 9in
How do I get this to figure out one of these answers? Thank you
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
LENGTH=(2W+8)
PERIMETER IS=2L+2W
64=2(2W+8)+2W
64=4W+16+2W
64-16=6W
48=6W
W=48/6
W=8 FOR THE WIDTH THUS THE LENGTH IS
2*8+8
16+8
24 IS THE LENGTH
PROOF
2*24+2*8=64
48+16=64
64=64
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