SOLUTION: Kayla designed a rectangular patio that was 3 times as long as it was wide and had a perimeter of 160 feet. What was the area of the patio?
Algebra.Com
Question 702353: Kayla designed a rectangular patio that was 3 times as long as it was wide and had a perimeter of 160 feet. What was the area of the patio?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the width. Then 
must represent the length. Since for any rectangle, 
you can write:
\ +\ 2w\ =\ 160)
Solve for . Then since the area is given by the length times the width, calculate 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
john had a square patio. after expanding the length by 20 ft and the wide by 10 ft the... (answered by nerdybill)
A rectangular field is five times as long as it is wide. If the perimeter of the field is (answered by rfer)
A rectangular field is two times as long as it is wide. If the perimeter of the field is... (answered by nic0le116)
A rectangular field is three times as long as it is wide. If the perimeter of the field... (answered by edjones)
A rectangular field is ten times as long as it is wide. If the perimeter of the field is... (answered by lwsshak3)
A rectangular field is eleven times as long as it is wide. If the perimeter of the field (answered by lwsshak3)
A rectangular field is five times as long as it is wide. If the perimeter of the field is (answered by josgarithmetic)
A rectangular field is seven times as long as it is wide. If the perimeter of the field... (answered by MathLover1)
A rectangular field is five times as long as it is wide. If the perimeter of the field is (answered by MathLover1)
