SOLUTION: The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than
twice the width. If the perimeter measures 48 inches, what is the measure of the le
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Question 676695: The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than
twice the width. If the perimeter measures 48 inches, what is the measure of the length
and width of the rectangle.
Answer by rm29924(97) (Show Source): You can put this solution on YOUR website!
the formula for the perimeter of a rectangle is perimeter=2(length)+2(width)
the width=x
the length is 6 inches less than twice the width
twice the width is 2x and six inches less means subtract 6
the length=2x-6
the perimeter = 48 inches
48=2(2x-6)+2x
48=4x-12+2x
combine like terms
48=6x-12
add 12 to both sides
60=6x
divide both sides by 6 to get x by itself
10=x
we know the length is 2x-6
2(10)-6
20-6
14
answer: the length is 14 inches
you can plug the answers into the equation to check it
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