SOLUTION: The perimeter of a rectangle is 46ft the length is 5 ft longer than its width what are the dimensions?

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 Question 626852: The perimeter of a rectangle is 46ft the length is 5 ft longer than its width what are the dimensions?Answer by mengayzkie(3)   (Show Source): You can put this solution on YOUR website!The formula for Perimeter is : P=2L+2W Given: P=46ft L=5ft + W (length is 5 ft longer that its width) Substitute the value of L to the formula P=2L+2W P = 2(5ft + W) + 2W P = 10ft + 2W + 2W P = 10ft + 4W Substitute the value of P (Perimeter from the given) 46ft = 10ft + 4W 46ft - 10ft = 4W 36ft = 4W Divide both sides of the equation by 4 9 = w or ====== w = 9 ====== Substitute the computed value of w to the equation L = 5ft + w L = 5ft + 9 ========== L = 14ft ========== Checking: Substitute the computed value of L and W in the original equation of P: P = 2L + 2W P = 2(14ft) + 2(9ft) P = 28ft + 18ft from the given; P = 46ft 46ft = 28ft + 18ft 46ft = 46ft checked!