SOLUTION: The perimeter of a rectangle is 46ft the length is 5 ft longer than its width what are the dimensions?

Question 626852: The perimeter of a rectangle is 46ft the length is 5 ft longer than its width what are the dimensions?
Answer by mengayzkie(3) (Show Source): You can put this solution on YOUR website!
The formula for Perimeter is :
P=2L+2W
Given:
P=46ft
L=5ft + W (length is 5 ft longer that its width)
Substitute the value of L to the formula P=2L+2W
P = 2(5ft + W) + 2W
P = 10ft + 2W + 2W
P = 10ft + 4W
Substitute the value of P (Perimeter from the given)
46ft = 10ft + 4W
46ft - 10ft = 4W
36ft = 4W
Divide both sides of the equation by 4
9 = w
or
======
w = 9
======
Substitute the computed value of w to the equation
L = 5ft + w
L = 5ft + 9
==========
L = 14ft
==========
Checking:
Substitute the computed value of L and W in the original equation of P:
P = 2L + 2W
P = 2(14ft) + 2(9ft)
P = 28ft + 18ft
from the given; P = 46ft
46ft = 28ft + 18ft
46ft = 46ft checked!
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