SOLUTION: The length of a rectangle is four times its width. If the area of the rectangle is 324ft^2 , find its perimeter.

Algebra.Com
Question 613238: The length of a rectangle is four times its width.
If the area of the rectangle is 324ft^2 , find its perimeter.

Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
w * 4w = 324 ft^2

4w^2 = 324 ft^2 ___ w^2 = 81 ft^2 ___ w = 9 ft

l = 4w = 4(9) = 36 ft

perimeter = 36 + 36 + 9 + 9 = 90 ft

RELATED QUESTIONS

The length of a rectangle is four times its width. If the perimeter of the rectangle is (answered by ReadingBoosters)
the Length of a rectangle is four times its width. If the area of the rectangle is 324... (answered by nyc_function)
The length of a rectangle is four times its width. If the area of the rectangle is... (answered by JBarnum)
The length of a rectangle is four times its width. If the area of the rectangle is... (answered by mananth)
The length of a rectangle is four times its width. If the area of the rectangle is... (answered by ewatrrr)
The length of a rectangle is four times its width. If the area of the rectangle is... (answered by Boreal)
The length of a rectangle is three times its width. If the area of the rectangle is ,... (answered by richard1234)
The length of a rectangle is four times its width. If the area of the rectangle is 196m2 (answered by nerdybill)
The length of a rectangle is four times its width. If the perimeter of the rectangle is (answered by mananth)