SOLUTION: The width of a rectangle is 3 inches and its area is 2 square feet. What is the length of this rectangle? Please help.

Algebra.Com
Question 611436: The width of a rectangle is 3 inches and its area is 2 square feet. What is the length of this rectangle?
Please help.

Found 2 solutions by radh, MathTherapy:
Answer by radh(108)   (Show Source): You can put this solution on YOUR website!
You'd have to convert feet to inches. We know that 1 foot = 12 inches. So the area is 24 inches. (2ft=24 inches).
So, we can write a formula as
Now, we simplify:
So, the length is 8 inches. :)

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
The width of a rectangle is 3 inches and its area is 2 square feet. What is the length of this rectangle?
Please help.

1 square foot = 144 square inches

2 square feet = 288 (144 * 2) square inches

Now, since area = 288 square inches, and width = 3 inches, then length = , or inches.

Send comments and “thank-yous” to “D” at MathMadEzy@aol.com

RELATED QUESTIONS

The width, w, of a rectangle is 2/3 its length, l. The width, w, of the rectangle is 10... (answered by josgarithmetic)
the length of a rectangle exceeds its width by 3 inches, and the area is 54 square... (answered by Fombitz)
If the length of a rectangle is decreased by 2 inches and its width is increased by 2... (answered by ankor@dixie-net.com)
The area of a rectangle is 18 square inches. THe length of the rectangle is twice its... (answered by rfer)
the width of a rectangle is 5 inches less than its length, and the area is 14 square... (answered by richard1234)
If the area of a rectangle is 2275 square feet and its width is 35 feet, what is its... (answered by Alan3354)
The area of a rectangle is 84 square inches. Its length and width are both whole numbers. (answered by scott8148)
the width of a rectangle is 5 inches less than its length, and the area is 150 square... (answered by sarah_adam)
The length of a rectangle is 6 inches more than its width. The area of the rectangle is... (answered by stanbon)