SOLUTION: the length of a rectangular garden is 5 m greater than the width. the area is 104m^2. find the dimensions of the garden.
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Question 599299: the length of a rectangular garden is 5 m greater than the width. the area is 104m^2. find the dimensions of the garden.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
A = LW
104 = (W+5)W
104 = W(W+5)
W^2 + 5W - 104 = 0
Now use the quadratic formula to solve
W = (-b+-sqrt(b^2-4ac))/(2a)
W = (-(5)+-sqrt((5)^2-4(1)(-104)))/(2(1))
W = (-5+-sqrt(25-(-416)))/(2)
W = (-5+-sqrt(441))/2
W = (-5+sqrt(441))/2 or W = (-5-sqrt(441))/2
W = (-5+21)/2 or W = (-5-21)/2
W = 16/2 or W = -26/2
W = 8 or W = -13
Throw out the negative solution to be left with the only solution of W = 8
So the width is 8 m and length is 13 m (since L = W+5 = 8+5 = 13)
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