SOLUTION: The length of a rectangle is 1 yard less than twice its width, and the area of the rectangle is 55yds^2 . Find the dimensions of the rectangle

SOLUTION: The length of a rectangle is 1 yard less than twice its width, and the area of the rectangle is 55yds^2 . Find the dimensions of the rectangle

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Question 590893: The length of a rectangle is 1 yard less than twice its width, and the area of the rectangle is 55yds^2 . Find the dimensions of the rectangle
Answer by ad_alta(240) (Show Source): You can put this solution on YOUR website!
Let 'l' be the length and 'w' the width. Then l+1=2w and l*w=55. Substituting the first equation into the second, we get (2w-1)*w=55. The quadratic equation gives w=11/2 and l=10.
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