SOLUTION: The length of a rectangle sign is 4 feet shorter than twice the width. The area of the rectangle is 48 squared feet. Could you help me find the dimensions of the sign?
I tried s
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Question 578999: The length of a rectangle sign is 4 feet shorter than twice the width. The area of the rectangle is 48 squared feet. Could you help me find the dimensions of the sign?
I tried setting it up as
l(w)= 48sq.ft
2w-4=l
But it's not quite working.
Help please and thanks :)
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
your equations are okay
substituting ___ (2w - 4)w = 48
dividing by 2 ___ (w - 2)w = 24 ___ w^2 - 2w - 24 = 0
factoring ___ (w - 6)(w + 4) = 0
w + 4 = 0 ___ w = -4 ___ negative value not realistic
w - 6 = 0 ___ w = 6
l = 2(6) - 4 ___ l = 8
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