LW = 4 2L + 2W = 10 Divide the second equation by 2 L + W = 5 Solve for L L = 5 - W Substitute in LW = 4 (5 - W)W = 4 5W - W² = 4 -W² + 5W - 4 = 0 Multiply through by -1 W² - 5W + 4 = 0 (W - 4)(W - 1) = 0 W - 4 = 0; W - 1 = 0 W = 4; W = 1 L = 5 - W L = 5 - W L = 5 - 4 L = 5 - 1 L = 1 L = 4 So either a 1cm x 4cm or a 4cm x 1 cm rectangle. Either of these, which are draw to scale:Edwin