SOLUTION: A rectangle has an area of 735cm2. Its length and width are whole numbers. what are the possibilities for the two numbers and which possibility gives the smallest perimeter?
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Question 564342: A rectangle has an area of 735cm2. Its length and width are whole numbers. what are the possibilities for the two numbers and which possibility gives the smallest perimeter?
Answer by ad_alta(240) (Show Source): You can put this solution on YOUR website!
Since the area ('A') is equal to the length ('l') times the width ('w'), this problem comes down to factoring 735. I'll write the possible answers as ordered pairs (l,w): (25,29), (5,145). It's easy to check that the perimeter ('P') [P=2l+2w] is smallest with l=25 and w=29.
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