SOLUTION: Please help in solving this equation: The perimeter of a rectangle is 234 meters, the rectangle is twice as long as it is wide, what are its length and width?

Question 561641: Please help in solving this equation:
The perimeter of a rectangle is 234 meters, the rectangle is twice as long as it is wide, what are its length and width?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 234 meters, the rectangle is twice as long as it is wide, what are its length and width?
:
I am going to show you how easy this is. Once you understand, you will be able to do this forever.
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Assuming the side of the rectangle are (L) length and (W) width, the perimeter:
2L + 2W = 234
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"the rectangle is twice as long as it is wide,", the equation for this statement:
L = 2W
:
In the first equation, we can replace L with 2W, then we have
2(2W) + 2W = 234
4W + 2W = 234
6W = 234
Divide both sides by 6
W =
W = 39 meters is the width
:
Remember it said the length is twice the width, therefore:
L = 2(39)
L = 78 meters is the length
:
:
Check this by finding the perimeter with these values
2(78) + 2(39) =
156 + 78 = 234
:
This is easy stuff, right?

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