SOLUTION: What is the area and perimiter of a rectangle with one side of 11 mm and a diagonal of 61 mm?

Question 558819: What is the area and perimiter of a rectangle with one side of 11 mm and a diagonal of 61 mm?
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x= length
11 = width
61 = diagonal

By Theorem of Pythagoras,

Reject x=-60!

Perimeter = 2W + 2L
Perimeter = 2*11+ 2*60
Perimeter = 22 + 120 = 132 mm

Area = L*W
Area = 11*60= 660 square mm.

For additional examples and explanation like this, please see my website. To go to my website, use the easy-to-spell and easy-to-remember link www.mathinlivingcolor.com. At the very bottom of this page, there is a link that will take you to my Homepage.

Once you are on my Homepage, for help with the Theorem of Pythagoras, look for the link "Basic, Intermediate, and College Algebra: One Step at a Time," and choose "Basic Algebra", "Chapter 2", "Section 2.10". For topics of Perimeters and Areas, look for the link near the bottom of my Homepage "Topics from Geometry."
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Seminole State College of Florida
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