SOLUTION: The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width
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Question 556944: The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
p=50
50=2(l+w)
l=9+w
50=2(9+w+w)
50=18+4w
32=4w
8=w
17=l
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